RULE OF DIFFERENTIATION

Mais informações

The "pizzagate" conspiracy theory

por Manuel Jose Martinez Carvajal

THRIFT SHOP finish

por JOSEPHINE SATRIADI JOSEPHINE SATRIADI

Table of Contents

por Vic Fiallo

RULES OF DIFFERENTIATION

por John Kelabu

ASSIGNMENT 2 - PRE FINAL BUSINESS MATHEMATICS II NAME : WAFIQAH BINTI WAHAB NO. MATRIC : 052870 PROGRAMME : DIPLOMA IN BANKING LECTURE NAME : MADAM HARDAYANNA ABD RAHMAN DUE DATE : THURSDAY, 9 JULY 2020

RULE OF DIFFERENTIATION

Main topic

RULE 5 : CHAIN RULE

= 15 (3x - 3)4

= 5 (3x - 3)4 (3)

Solution : f' (x) = 5 (3x-3)4 (3x-3)1

Example : f (x) = (3x - 3)5

f' (x) = n (ax + b)n-1 (ax + b)1

f (x) = (ax + b)n

RULE 6 : PRODUCT RULE

= -24x2 + 20x + 12

= -16x2 + 20x - 8x2 + 12

f' (x) = (4x - 5)(-4x) + (-2x2 + 3)(4)

v' = -4x

v = -2x2 + 3

u' = 4

Solution : u = 4x - 5

Example : (4x - 5) (-2x2 + 3)

f' (x) = uv' + vu'

h(x) = u, g(x) = v

f (x) = h(x)g(x)

RULE 7 : QUOTIENT RULE

= 3 / (2x +1)2

= 6x + 3 - 6x / (2x + 1)2

f' (x) = (2x + 1)3 - 3x(2) / (2x + 1)2

v' = 2

v = 2x + 1

u' = 3

Solution : u = 3x

Example : 3x / 2x + 1

f'(x) = vu' - uv' / v2

h(x) = u, g(x)

f (x) = h(x) / g(x)

RULE 4 : SUM RULE

Solution : f' (x) = 4x3 + 4

Example : f (x) = x4 + 4x

f (x) = h' (x) + g' (x)

f (x) = h (x) + g (x)

RULE 3 : POWER RULE

Solution : 9x8

Example : x9

f' (x) = nxn-1

f (x) = xn

Solution : f' (x) = 8

Example : f (x) = 8x

f' (x) = m

f (x) = mx

RULE 1 : CONSTANT RULE

Solution : f' (x) = 0

Example : f (x) = 13

f' (x) = 0

y = f (x) = c